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{24.NS.8} Steph places a point on a coordinate plane at (3, -2). She wants to place another point across the x-axis, and it must be 7 units away. Where will Steph place the other point?

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We have been given that Steph places a point on a coordinate plane at (3, -2). She wants to place another point across the x-axis, and it must be 7 units away. We are asked to find the point, where Steph will place it.

Since the point will be across x-axis, so x-coordinate of of other point will be same that is 3.

Now we will use distance formula to find the coordinate of other point.


D=√((x_2-x_1)^2+(y_2-y_1)^2)


7=√((3-3)^2+(y-(-2))^2)


7=√(0+(y+2)^2)


7=√((y+2)^2)

Square root will cancel out with square.


7=y+2


7-2=y+2-2


5=y

Therefore, the Steph will point the other point at
(3,5).

User EAzevedo
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