Answer:
Volume of water
Initial temperature of the solution
Final temperature of the solution
Mass of NH₄Cl
Step-by-step explanation:
There are two heat transfers involved in this experiment.
Heat of solution of NH₄Cl + heat lost by water = 0
q₁ + q₂ = 0
nΔH + mCΔT = 0
nΔH = -mCΔT
ΔH = -mCΔT/n
So, you must measure
- the volume of water (you will probably use its density to calculate its mass)
- the initial and final temperatures of the solution (to calculate ΔT)
- the mass of NH₄Cl (to calculate the number of moles)
You will probably assume that the specific heat capacity of the solution is the same as that of water, so you won't be measuring it.