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How many joules of heat energy are required to raise the temperature of

100 grams of water from 21°C to 23°C?

User Lbsn
by
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1 Answer

2 votes

Answer:

836.8J

Step-by-step explanation:

Heat energy = ?

Mass = 100g

Initial temperature (T1) = 21°C

Final temperature (T2) = 23°C

Specific heat capacity of water (c) = 4.184J/g°C

To solve this question, we'll need to use the formula for calculating heat energy of a substance.

Q = mc∇t

Q = heat energy of substance

M = mass of substance

C = specific heat capacity of substance

∇t = change in temperature = T2 - T1

Q = 100 × 4.184 × (23 -21)

Q = 418.4 × 2

Q = 836.8J

The heat energy required to raise 100g of water from 21°C to 23°C is 836.8J

User Ananth Joshi
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7.6k points