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The three angles of a triangle form an A.P. If the largest angle is twice than the smallest angle find theee angles of that triangle​

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Answer:

Let the angles be (a-d), a , (a+d)

a-d + a + a + d = 180 (angle sum property)

3a = 180

a = 60

Given:

a+d = 2(a-d)

60 + d = 2(60 - d)

60 + d = 120 - 2d

3d = 120 - 60

d = 20

Angles are : 40 , 60 , 80

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