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A store is selling two different types of cheese. One type sells for $3.75 a pound and a second

type sells for $4.55 a pound. How many pounds of the $3.75 cheese would the store need to mix
together with the $4.55 cheese to get a 45-pound mixture that sells for $4.05 a pound (round your
answer to the nearest pound?

User ASX
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1 Answer

3 votes

Answer:

28 pounds

Explanation:

Let x represent the amount of $3.75 cheese needed for the mix. Then the total cost of the mix is ...

3.75x +4.55(45 -x) = 4.05(45)

-0.80x = 45(4.05 -4.55) = -0.50(45) . . . . . simplify, subtract 4.55(45)

x = (5/8)(45) = 28.125 . . . . . . . . . . . . . .divide by -0.80

To the nearest pound, 28 pounds of $3.75 cheese would be needed in the mix.

User John Yang
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