Final answer:
When two identical cells with an emf of 2V and internal resistance of 1.0Ω are connected in parallel to an external load of 1.5Ω, the current in the circuit is 1.33 Amps.
Step-by-step explanation:
When two identical cells with an emf of 2V and an internal resistance of 1.0Ω are connected in parallel, the total emf remains the same, but the total internal resistance is reduced. The current flowing through the external load can be calculated using Ohm's Law: I = V/R. In this case, the voltage (V) is the total emf of the parallel combination of cells, which is 2V, and the resistance (R) is the external load resistance, which is 1.5Ω.
So, I = 2V / 1.5Ω = 1.33A. Therefore, the current in the circuit is 1.33 Amps.