Answer:
in the word strawberry we have:
s ---- 1 time
t----- 1 time
r -----3 times
a---- 1 time
w ---- 1 time
b ---- 1 time
e ---- 1 time
y ---- 1 time.
a total of 10 letters
The probability of finding a given letter is equal to the amount of times that we have that letter in the word divided by the number ofall the letters in the word.
Prob of letter S or B.
We have only one S and one B so here we have 2 options
the prob is P = 2/10 = 1/5 = 0.20
Prob of letter R or C.
We have 3 times letter R and zero times letter C, so we have 3 options:
the prob is P = 3/10 = 0.3
A consonant or D: We have one S, one T, 3 Rs, one W, one B and one Y, (we have no letter D in the word) so the number of options is:
1 + 1 + 3 + 1 +1 + 1 = 8 options
the prob is p = 8/10 = 0.80
For a letter in the word kramer.
the letters in common between kramer and strawberry are:
r, e and a.
In our 10 cards we have 3 times letter R, 1 time the letter A and one time the letter E, a total of 3 + 1 + 1 = 5 options:
The prob is p = 5/10 = 0.5