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In triangle ABC angle a equals 72° side C equals 61 and angle B equals 16° find side a to the nearest 10th

1 Answer

3 votes

Answer:

58.0 units

Explanation:

In order to use the law of sines, we need to know angle C. It will be the angle that brings the total of all angles to 180°.

C = 180° -A -B = 180° -72° -16°

C = 92°

The law of sines tells us ...

a/sin(A) = c/sin(C)

a = c·sin(A)/sin(C) = 61·sin(72°)/sin(92°)

a ≈ 58.0 . . . . units

In triangle ABC angle a equals 72° side C equals 61 and angle B equals 16° find side-example-1
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