Question

There are some sweet in a bag. The sweet are green, red or yellow. The probability of choosing a green sweet at random from the bag is 3/11 the probability of choosing a red sweet at random from the bag is 5/11 what is the probability of choosing a yellow sweet from the bag? Give your answer as a fraction

Answer 1

the probability of choosing a yellow sweet from the bag is
`(3)/(11)`

Explanation:

Given that;

The probability of choosing a green sweet at random from the bag is 3/11 the probability of choosing a red sweet at random from the bag is 5/11

probability of choosing a green sweet. is 3/11

probability of choosing a red sweet. is 5/11

probability of choosing a yellow sweet is x

we sum the probabilitity of green and red sweet

`(3)/(11) + (5)/(11) = (8)/(11)`

To get the probability of choosing a yellow sweet

we subract the sumation of (probabilitity of green and red sweet) and 1

i.e 1 - 8/11

`x =1-(8)/(11)`

=
`(3)/(11)`

Thus ,the probability of choosing a yellow sweet from the bag is
`(3)/(11)`

Answer 2

`p = (3)/(11)`

Explanation:

We have these following probabilities:

3/11 probability of choosing a green sweet.

5/11 probability of choosing a red sweet.

p probability of choosing a yellow sweet.

The sum of these probabilities is decimal 1. So

`p + (3)/(11) + (5)/(11) = 1`

`(11p + 3 + 5)/(11) = 11`

`11p + 8 = 11`

`11p = 3`

`p = (3)/(11)`