(6t^4-t+1) - (6t^3-4t) - QAmmunity.org

asked Mar 10, 2021 127k views

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(6t^4-t+1) - (6t^3-4t)

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Answer:

$= 6 {t}^(4) - 6 {t}^(3) + 3t + 1$

Explanation:

$6 {t}^(4) - t + 1 - 6 {t}^(3) + 4t \\ = 6 {t}^(4) - 6 {t}^(3) + 3t + 1$

Will Kanga answered Mar 16, 2021

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