Question

HELP PLEASE!!!! Both of the questions follow with the chart

Answer 1

Let's denote:

probability that a person paid regular admission P(A)

probability that a person purchased no snack P(B)

probability that a person got discount on admission P(C)

probability that a person purchased snack P(D)

For picture 1

Applying Bayes theorem, we have:

probability that a person paid regular admission, given that person purchased no snack : P(A|B) = P(A ∩ B)/P(B) = (108/240)/(144/240) = 108/144 = 0.75

=> Option D is correct

For picture 2

As shown in picture, we have:

probability that a person got discount on admission and purchased snack:

P(C ∩ D) = 24/240 = 0.1

=> Option C is correct

Hope this helps!

:)

Answer 2

1. 0.75

2. 0.25

Explanation:

Let's start off with number 1

There is only 2 answers that would make sense.

0.6 and 0.75

But only one is the answer

To find the answer you have to go to the columns that represent the equation

Then you divide

108/144

= 0.75

Now in number 2

You have to place the information in the graph where it corresponds and you get the numbers 24/96

Now divide

24/96

=0.25

Hope this helped :)

Have a good one!