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Solve for x. 8x-4=x^2+5x-15

User Mark Ni
by
8.1k points

2 Answers

4 votes

Answer:

x=3/2+ −1/2√53 or x=3/2+ 1/2√53

Explanation:

User Wentjun
by
8.5k points
4 votes

Answer:


(3 + √(53) )/(2) and \: (3 - √(53) )/(2)

Explanation:


8x-4= {x}^(2) +5x-15

=> we try to make one side "0". I choose left side. So;

=> add -8x both side. Because left side has +8x


8x-4 - 8x= {x}^(2) +5x-15 - 8x


-4= {x}^(2) - 3x -15

=> add +4 both side. Because left side has -4


-4 + 4= {x}^(2) - 3x -15 + 4


0= {x}^(2) - 3x -11


{x}^(2) - 3x -11 = 0

Use quadratic formula :

  • What is quadratic formula
  • solving for x

I solved in the picture, you can look it :)

Hope this helps ^-^

Solve for x. 8x-4=x^2+5x-15-example-1
User Connexo
by
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