Question

The function that has an x-intercept of -2 and a y-intercept of - 2/3

Answer 1

Explanation:

`eq. of a line in intercept form~ is \\(x)/(a)+(y)/(b)=1\\here~a=-2,b=-(2)/(3)\\reqd.~eq.~is\\(x)/(-2)+(y)/(-(2)/(3) ) =1\\(x)/(-2) +(3y)/(-2) =1\\x+3y=-2\\3y=-x-2\\y=-(1)/(3)x-(2)/(3)`

Answer 2

y = (-1/3)x - 2/3

Explanation:

y = mx + c

When x = 0, y = -2/3

-2/3 = 0 + c

c = -2/3

When y = 0, x = -2

0 = -2m - 2/3

-2m = 2/3

m = -1/3

y = (-1/3)x - 2/3