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Find the area of the figure,
(Sides meet at night angles.)



Find the area of the figure, (Sides meet at night angles.) ​-example-1
User TheZver
by
8.2k points

2 Answers

7 votes

Answer:

The area of the figure is 15 inches.

Explanation:

Let's break up this figure into parts (see the figure.)

The formula for the area of a rectangle is
A=l×
w, where
l is the length and
w is the width.

Since we broke up the figure, we can find the areas of all the rectangles and add them together to find the total area.


  • A_R_e_c_t_a_n_g_l_e _1=6 square inches

  • A_R_e_c_t_a_n_g_l_e _2=3 square inches

  • A_R_e_c_t_a_n_g_l_e _3=6 square inches
  • Total area =
    A_R_e_c_t_a_n_g_l_e _1+A_R_e_c_t_a_n_g_l_e _2+A_R_e_c_t_a_n_g_l_e _3 , which is 15 square inches (
    in.^(2))
Find the area of the figure, (Sides meet at night angles.) ​-example-1
User AlphaBeta
by
8.8k points
4 votes

Answer:

15 in^2

Explanation:

Find the area of the vertical rectangle

A = l*w

A = 6*2 = 12 in^2

Now find the area of the horizontal rectangle

A = l*w

= 3*1 = 3in^2

Add them together

12+3 =15 inch^2

User Sharada
by
8.3k points

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