Question

Evaluate 6t - 20-32u when t = 6 and u = 1/5

Answer 1

48/5= 9 4/5

Explanation:

first substitute the variable

6(6)-20-32(1/5)

36-20-32/5

16-32/5

get the both numbers to have the same denominator

16 times 5/5= 80/5

now subtract the both numbers

80/5-32/5= 48/5

48/5= 9 4/5

Answer 2

48/5

Explanation:

6t - 20-32u

Let t= 6 and u = 1/5

6*6 - 20 -32(1/5)

Multiply

36 -20 -32/5

16 - 32/5

Get a common denominator

80/5 -32/5

48/5