Question

A positive test charge of 8.5 × 10 negative 7 Columbus experiences a force of 4.1 × 10 negative 1 N calculate the electric field created by the positive test charge also specify the direction of the electric field with respect to the force

Answer 1

Comments/Reasoning Calculations/Results

I used the equation for calculating electric field strength. E = F/q

I substituted the values of F and q in the equation to get

this value of E E= (4.1 x10-1)/(8.5 x10-7)

The electric field strength is 4.8 × 105 newtons/coulomb

Step-by-step explanation:

edmentum sample answer

Answer 2

Step-by-step explanation:

direction of electric field is same as that of force experienced by the test charge