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The graph of the function f(x) =ax2+bc+c is given below. Could the factors of f(x) be (x+2) and (x+4)? Based on the graph, explain why or why not.

The graph of the function f(x) =ax2+bc+c is given below. Could the factors of f(x-example-1
User PC Luddite
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Answer:

neither can be a factor

Explanation:

If (x -a) is a factor, then value of the function will be zero at x=a. Here, the function has a value of zero (x-intercept) at x = -1 and x = 3. Hence (x+1) and (x-3) are factors, but (x+2) and (x+4) are not. The function is non-zero at x=-2 and x=-4.

User MattW
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