Question

An object is moving at a velocity of 3m/s. It accelerates to a velocity of 5.5m/s over a time of 9 s. What acceleration did it experience?

Answer 1

Acceleration(a) =
`\displaystyle(v - u)/(t)`

v = final velocity = 5.5 m/s

u = initial velocity = 3 m/s

t = time = 9s

`\displaystyle a = (3-5.5)/(9)`

`a = \displaystyle(-2.5)/(9)`

`a = -0.278 \ m/s^2` (approx)

Answer 2

The acceleration experienced by the object when moved over a time of 9 seconds with its velocity is 0.277m/s^2

Step-by-step explanation:

Acceleration is the rate of change of velocity

The change in velocity implies that the object moves with an initial velocity and stopped with a final velocity.

The object move with a velocity of 3.0m/s

This implies that the initial velocity of the moving object was 3m/s

The object gets to its final position over a time of 9 seconds with a velocity of 5.5m/s

`a = (v - u)/(t) \\Where,\\v = final velocity\\u = initial velocity\\t = time\\\\u = 3m/s\\v = 5.5m/s\\t =9 secs\\\\a = (5.5 - 3)/(9) \\\\a = (2.5)/(9) \\a= 0.277 m/s^(2)`