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Write an equation of the circle with center (2,-3) and radius 8.

2 Answers

4 votes

Answer:


(x-2)^2+(y-3)^2=64

You may simplify further

Explanation:

The eqn. of a circle with centre (h,k) and radius r is given by,


(x-h)^2+(y-k)^2=r^2\\(x-2)^2+(y-3)^2=8^2\\(x-2)^2+(y-3)^2=64\\

User Dakatine
by
8.6k points
2 votes

Answer:

(x-2)^2+ (y+3)^2 = 64

Explanation:

We can write the equation of a circle as

(x-h)^2+ (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

(x-2)^2+ (y- -3)^2 = 8^2

(x-2)^2+ (y+3)^2 = 8^2

(x-2)^2+ (y+3)^2 = 64

User Unfulvio
by
7.6k points

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