Question

A party rental company has chairs and tables for rent. The total cost to rent 3 chairs and 8 tables is $58. The total cost to rent 5 chairs and 2 tables is $23. What is the cost to rent each chair and each table?

Answer 1

Equations::

4c + 8t = 58

2c + 3t = 23

----------------

Modify for elimination:

4c (4c*1) + 8t (8t*1)= 58

4c (2c*2) + 6t (3t*2)= 46

---------------------

Subtract and solve for "t":

2t (8t-6t) = 12

t = $6 (cost of one table)

-----

Solve for "c":

2c + 3t = 23

2c + 18 = 23

2c = 5

c = $2.50 (cost of one chair)