Question

Solve the following quadratic for the values x

Answer 1

`{x}^(2) + 6x - 27 = 0 \\ D= {6}^(2) - 4 * ( - 27) = 36 + 108 = 144 = {12}^(2) \\ x_1= ( - 6 + 12)/(2) = 3 \\ x_2= ( - 6 - 12)/(2) = - 9`

Answer: x=3; x=-9

Answer 2

x² + 6x - 27 = 0

x² + 9x - 3x - 27 = 0

x ( x + 9 ) - 3 ( x + 9 ) = 0

( x + 9 ) ( x - 3 ) = 0

Thus ,

x = -9 or x = 3

I hope it helps you

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