Question

Help me plzzzzzzz!!!!


`{y}^(2) + 14 = 3 {y}^(2) * 5`​

Answer 1

y = ± 1

Explanation:

Given

y² + 14 = 3y² × 5, that is

y² + 14 = 15y² ( subtract y² from both sides )

14 = 14y² ( divide both sides by 14 )

1 = y² ( take the square root of both sides )

±
`√(1)` = y , that is

y = ± 1

Thus y = - 1 or y = 1

Answer 2

`y=1,\:y=-1`

Explanation:

`y^2+14=3y^2\cdot \:5\\\y^2+14-14=3y^2\cdot \:5-14\\y^2=15y^2-14\\y^2-15y^2=15y^2-14-15y^2\\-14y^2=-14\\(-14y^2)/(-14)=(-14)/(-14)\\y^2=1\\\\y=√(1),\:y=-√(1)\\y=1,\:y=-1`