Question

A stunt performer falls off a wall that is 2.5 m high and then lands on a mat.

What is his impact velocity?
A. 5.6 m/s
B. 3.9 m/s
C. 7.0 m/s
D. 9.4 m/s
SUB

Answer 1

His impact velocity is 7 m/s.

Step-by-step explanation:

A stunt performer falls off a wall that is 2.5 m high and then lands on a mat. Let v is his impact velocity.

Concept used : Law of conservation of energy

Using the law of conservation of energy of the person such that,

`(1)/(2)mv^2=mgh\\\\v=√(2gh)`

g is acceleration due to gravity, g = 9.8 m/s²

`v=√(2* 9.8* 2.5)\\\\v=7\ m/s`

So, his impact velocity is 7 m/s.