Question

Find the number of real solutions of the equation x^2+10x+35=0 using the discriminant:(b^2-4ac)

Answer 1

Answer: No real roots or solutions

Explanation:

X^2+10x+35=0 using this equation you can tell that a=1, b=10, and c=35. Using the numbers for the formula,

b^2 - 4ac, it will look like this... 10^2-4(1)(35). Next step is the exponent. It will look like this now, 100-4(1)(35), the next step is to multiply. 100-140= -40. When the discriminant is negative, there are no real roots, or solutions.