Question

this is easy but i'm lazy someone explain how to find the solution to an equation like (x+1)(2x-3) or (x-8)^2 IM GIVING 65 POINTTSS

Answer 1

make equation = 0

Explanation:

In first case your equation is factored so just = 0

(x+1)(2x-3) = 0

Product is zero if any factor is zero so (x+1) = 0, (2x-3) = 0

Solve for x: x= -1, x= 3/2

If (x-8)^2 is given than you need to factor it first and then do the same as in first example.

(x-8)^2 = (x-8)(x-8)

(x-8)=0 , x=8

This is double zero.