Question

While moving a box 10.0 m across the floor, Sam pushes with a force of 150 N to the right. The force friction acting on the box is 25.0 N to the left. What is the net work done on the box by these 2 forces

Answer 1

Explanation:required formula is

W 1=F*S

W1=work done by Sam =?

F=force applied by sam=150N

S=displacement =10m

again

W2=F*S

W2=work done by friction =?

S=displacement =10m

F=friction =25N

W=W1-W2=net work done

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