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A ball is launched into the sky at 48 feet per second from a building 48 feet tall. The equation for the ball’s height h at time t seconds is h = -16t2 + 48t + 48. When will the ball strike the ground?
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A ball is launched into the sky at 48 feet per second from a building 48 feet tall. The equation for the ball’s height h at time t seconds is h = -16t2 + 48t + 48. When will the ball strike the ground?

User Kmore
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8.1k points

1 Answer

4 votes

Answer:

4 seconds I believe

Explanation:

User Jontem
by
8.2k points
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