A ball is launched into the sky at 48 feet per second from a building 48 feet tall. The equation for the ball’s height h at time t seconds is h = -16t2 + 48t + 48. When will the ball strike the ground?

asked Mar 14, 2021 101k views

4 votes

by Kmore

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4 votes

Answer:

4 seconds I believe

Explanation:

Jontem answered Mar 19, 2021

4.4k points

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