Question

The sum of three numbers is 141. The first number is 9 more than the third. The second number is 4 times the third. What are the numbers?

Answer 1

x...third number

4x...second number

x-9...first number

(x)+(4x)+(x-9)=141

x+4x+x-9=141

6x-9=141

Let's add 9 to both sides...

9+6x-9=141+9

6x=150

Let's divide both sides by 6...

(6x)/6=150/6

x=25

third number...25

second number...(4)(25)=100

first number...(25-9)=16

Let's check our work...

25+100+16=141

141=141