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PLEASE help ………………….

PLEASE help ………………….-example-1
User Dhanapal
by
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1 Answer

8 votes

Answer:

1st Part: Infinitely many solutions

2nd Part: Exactly one solution

3rd Part: No Solutions

Explanation:

First Part: 4(x - 1) = 4x - 4

Distribute. 4x - 4 = 4x - 4

Because the equations are the same, any value can be substituted for x and both the equations' values would still be equivalent.

2nd Part:

x + 4 = 4(x + 1)

x + 4 = 4x + 4

Minus 4 both sides

x = 4x

Only 0 can make this equation true, meaning it only has ONE solution.

Third Part:

4x + 1 = 4(x - 1)

Distribute.

4x + 1 = 4x - 1

Subtract 4x both sides

1 = -1

Obviously, 1 and -1 are not equivalent, meaning there are no value that can be substituted for x to make this equation true.

User Willtardy
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