Question

F(x)=x^2+4x+12 vertex and minimum value of f(x) 20 points to the best answer.

Answer 1

(-2, 8)

Explanation:

For the function f(x) = ax² + bx + c

Vertex is found by:

• x = -b/(2a)

For the given function

• f(x)=x² + 4x + 12

Vertex is:

• x = -4/2 = -2

And the minimum value is:

• f(-2) = (-2)² + 4(-2) + 12 = 4 - 8 + 12 = 8

So the coordinates of vertex is (-2, 8)