Question

In the right triangle shown, m\angle J = 60^\circm∠J=60 ∘ m, angle, J, equals, 60, degrees and JL = 6\sqrt{3}JL=6 3 ​ J, L, equals, 6, square root of, 3, end square root. How long is JKJKJ, K?

Answer 1

the proof is in the picture

Explanation:

Answer 2

`|JK|=3√(3)`

Explanation:

The diagram of the triangle is drawn and attached,

From trigonometric ratios,

`cos \theta =(Adjacent)/(Hypotenuse) \\cos60^\circ =(|JK|)/(|JL|)\\ 0.5=(|JK|)/(6√(3) )\\$Cross multiply$\\|JK|=0.5*6√(3)\\|JK|=3√(3)`