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What is the equation of the circle passing through the point (6,5) and centered at (3.-4)?

User Gambisk
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1 Answer

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Answer:

(x - 3)² + (y + 4)² = 90 or [3√10)²

Explanation:

We need to calculate the radius of this circle. To do this we calculate the distance from the center (3, -4) to the point (6, 5).

As we move from (3, -4) to (6, 5), x (the run) increases by 3 and y (the run) increases by 9. Thus, the distance between these points, according to the Pythagorean Theorem, is

r = √[3² + 9²], or r = √90, or r = 3√10.

Using the standard equation of the circle, (x - h)² + (y - k)² = r², we obtain

(x - 3)² + (y + 4)² = 90 or [3√10)²

User Minebomber
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