Answer:
D) 6.02 kJ/mol
Step-by-step explanation:
Hello,
In this case, since 200kJ melted 1.5 kg of ice (2.0kg-0.5kg), we can compute the melted moles:

Then, we compute the molar enthalpy of fusion by diving the melted moles to the applied heat:

Hence answer is D) 6.02 kJ/mol.
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