Answer:
Angles are 3x, 4x =
![60\°,80\°](https://img.qammunity.org/2021/formulas/mathematics/high-school/26rnpyqj14fmx866p2ta4suvmn4tkaia7m.png)
Angles from lowest to highest:
![60\°,60\°,80\°,140\°](https://img.qammunity.org/2021/formulas/mathematics/high-school/3rz4srwhwu7il4zee6xmkkap2ewyec27kw.png)
Explanation:
Given: Two angles of a quadrilateral measure 140° and 80°. The other two angles are in a ratio of 3:4.
To find: value of x, measures of those two angles and
Also, to list the measures of the other two angles from lowest to highest.
Solution:
According to angle sum property of a quadrilateral, sum of angles of a quadrilateral is 180°.
Let the two angles be 3x and 4x
![3x+4x+140\°+80\°=360\°\\7x+220\°=360\°\\7x=360\°-220\°=140\°\\x=(140\°)/(7)=20\°\\](https://img.qammunity.org/2021/formulas/mathematics/high-school/h1ky40re2lrdr4glnxmb55apkmepvwvk8d.png)
So, angles are as follows:
![3x=3(20\°)=60\°\\4x=4(20\°)=80\°](https://img.qammunity.org/2021/formulas/mathematics/high-school/tpycqtjkuti5jl0qjghh6hhj9qua1mp3cq.png)
Angles from lowest to highest:
![60\°,60\°,80\°,140\°](https://img.qammunity.org/2021/formulas/mathematics/high-school/3rz4srwhwu7il4zee6xmkkap2ewyec27kw.png)