Question

What are the solutions to this quadratic equation? x^2+6x-5=0

Answer 1

`x = -3+√(14) \\x=-3-√(14)`

Explanation:

x + 6x - 5 = 0

Since you can't factor the equation, use the quadratic formula.

Your equation is already in the form of ax + bx + c.

`x=\frac{-b\frac{+}{} \sqrt{b^(2) -4ac} }{2a}`

Based on your equation a = 1 b = 6 c = -5. Plug in the numbers and solve for x.

`x = \frac{-6\frac{+}{} \sqrt{6^(2) -4(1)(-5)} }{2(1)} \\x = \frac{-6\frac{+}{} √(36+20 ) }{2} \\x=\frac{-6\frac{+}{}√(56) }{2} \\x=\frac{-6\frac{+}{}2√(14) }{2} \\\\x = -3+√(14) \\x=-3-√(14)`