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SOMEONE COULD HELP ME!?

The following tables list the times and distances traveled by two cyclists who start in the
same instant from the same origin and in the same direction in a straight line: don't forget to change
units.

SOMEONE COULD HELP ME!? The following tables list the times and distances traveled-example-1

1 Answer

1 vote

Answer:

1) 33km

2a) 18km/hr

b) Speed of cyclist B not constant

See below for explanation

Step-by-step explanation:

The question is incomplete as what is to be determined from the table wasn't specified.

From the question and table, we can tell two cyclists moving at the same direction covered different distances at same time interval.

1) Let's determine their distance apart after 120min and 2) speed of each cyclist

Solution:

1) Distance covered by cyclist 1:

3km + 9km + 18km + 36km = 66km

Distance covered by cyclist 2:

0.78km + 3.42m + 10.08m + 32.12km

Since the units are not the same, Let's convert the unit (from meters to km)

1000m = 1km

3.42m= 0.00342km

10.08m = 0.01008km

Distance covered by cyclist 2:

0.78km + 0.00342km + 0.01008km + 32.12km = 32.9135km

Their distance apart after 120min (2hrs):

60min = 1hr

120min = 2hrs

= Distance covered by cyclist 1 - Distance covered by cyclist 2

= 66 - 32.9135 = 33.0865km

Their distance apart after 120min (2hrs) = 33km (nearest km)

2a) Speed = distance/time

Time interval = 10min, 30min, 60min, 120min respectively

In hours: (1/6)hr, (1/2)hr, 1hr, 2hrs respectively

Speed of cyclist 1 (km/hr)= distance/time

For each time interval(km/hr):

=3/(1/6); 9/(1/2); 18/1; 36/2

= 18km/hr; 18km/hr; 18km/hr; 18km/hr

Therefore, the speed of cyclist 1 is constant = 18km/hr

2b) Speed of cyclist 2:

For each time interval(km/hr):

= 0.78/(1/6); 0.00342/(1/2); (0.01008/1); (32.12/2)

= 4.68km/hr; 0.00684km/hr; 0.0108km/hr; 16.56km/hr

The speed of cyclist 2 is not constant.

User Sergej Panic
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