Question

A gas occupies a volume of 255.0 L at 125.0C and 221 kPa. What is the volume of the gas at STP?

Answer 1

Step-by-step explanation:

We shall apply gas law equation

`(P_1V_1)/(T_1) =(P_2V_2)/(T_2)`

P₁ = 221 X 10³

V₁ = 255 L

T₁ = 273 + 125

= 398 K

P₂ = 1.01 x 10⁵ ( Standard pressure )

V₂ = ?

T₂= 273 K ( standard temperature is 0 degree )

Putting the values above in the gas equation

`(221000* 255)/(398) =(101000V_2)/(273)`

V₂ = 382.73 L .