Question

1 point

Using the balanced chemical equation; how many moles of ammonia will
be made if 12g of hydrogen gas is reacted with excess nitrogen?
(Remember Hydrogen gas is diatomic) *
N2 + 3 H2 → 2 NH3 (AH = -92.4 kJ.mol-1)
8 moles
6 moles
4 moles
2 moles

Answer 1

To find how many moles of ammonia are produced from 12g of hydrogen gas, we first find the number of moles of hydrogen (6 moles) and then use the balanced equation, which tells us that 6 moles of H₂ will produce 4 moles of ammonia.

Step-by-step explanation:

To determine how many moles of ammonia will be made from 12g of hydrogen gas (H₂) when reacted with excess nitrogen (N₂), we first need to calculate the moles of hydrogen used in the reaction. Hydrogen gas is diatomic (H₂), with a molar mass of approximately 2 g/mol. Using the molecular weight, we calculate the number of moles of H₂ as follows:

• Number of moles of H₂ = 12 g / 2 g/mol = 6 moles H₂

The balanced chemical equation N₂ + 3 H₂ → 2 NH₃ indicates that 3 moles of H₂ produce 2 moles of NH₃. With 6 moles of H₂, this would produce:

• Number of moles of NH₃ = (6 moles H₂ / 3 moles H₂) x 2 moles NH₃ = 4 moles NH₃

Answer 2

4 moles

Step-by-step explanation:

Step 1: Write the balanced equation

N₂ + 3 H₂ → 2 NH₃ (ΔH = -92.4 kJ.mol⁻¹)

Step 2: Calculate the moles of hydrogen

The molar mass of H₂ is 2.0 g/mol. The moles corresponding to 12 grams are:

`12g * (1mol)/(2.0g) =6.0mol`

Step 3: Calculate the moles of ammonia

The molar ratio of H₂ to NH₃ is 3:2. The moles of ammonia produced from 6.0 moles of hydrogen are:

`6.0molH_2 * (2molNH_3)/(3molH_2) =4 molNH_3`