Answer:
Option c. is correct
Explanation:
The standard deviation is a measure of the amount of dispersion in a set of values.
Mean of a normal distribution (m) = 154
Standard deviation (s) = 15
z-score = 2.2
To find: value (x) that has a z-score of 2.2
z-score is given by
![z=(x-m)/(s)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/w2w5mkuq9498iswzlizovpionj2bcjerkn.png)
Put
![z=2.2,.m=154,s=15](https://img.qammunity.org/2021/formulas/mathematics/middle-school/paa2a86oca8jap2599xpvlg9wbmswxufnu.png)
![2.2=(x-154)/(15)\\15(2.2)=x-154\\33=x-154\\x=33+154\\=187](https://img.qammunity.org/2021/formulas/mathematics/middle-school/li7hfnenzd7rgstt2t6db6x8mhg2e3tk2k.png)
Option c.is correct