Question

the endpoints of the diameter of a circle have the coordinates (3,8) and(9,16) what are the coordinates of the center

Answer 1

The coordinates of the center of this circle will be the average between the extreme points


C = ( (xo+x1)/2 , (yo+y1)/2)

Where,

xo = 3 and x1 = 9

yo = 8 and y1 = 16

Then us stay with"


C = ( (3+9)/2 , (8+16)/2)

C = ( 12/2 , 24/2)

C = ( 6 , 12 )