Answer:
the volume of the sphere is
![33.51 in^(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/5crmx5iy1ucc8uij4gksez97sl9a9syq38.png)
Explanation:
This problem bothers on the mensuration of solid shapes, sphere and cube.
Given data
Volume of cube v = 64 cubic inches
since we are dealing with a cube the height and the radius of the sphere is same as the sides of the cube,
we know that volume of cube is expressed as
![v= l*b*h](https://img.qammunity.org/2021/formulas/mathematics/high-school/ld1pnz2gg31eug2x7s52jvw90t2nq5ul2a.png)
![v=l^(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/9a8p4dzq4l03jtyb97e1zuzga7o6erd39u.png)
![64= l^(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/vjv84jd9o5b3avau7m6ggwrfy3pspm6w5p.png)
![l= \sqrt[3]{64}](https://img.qammunity.org/2021/formulas/mathematics/high-school/gx9bw61t1cg7o3rozc6nchrfngxxxgvcgp.png)
![l= 4 in](https://img.qammunity.org/2021/formulas/mathematics/high-school/9j17ana4l3ecoyj5qp9gg02dt672mhuzcd.png)
also diameter d=length l
Diameter d=
Radius r =
=
=
![{2 in}](https://img.qammunity.org/2021/formulas/mathematics/high-school/7vtsheiqfkkkbngl67cbqrmkeecxvr31dz.png)
Height h=
![4in](https://img.qammunity.org/2021/formulas/mathematics/high-school/55okoiki7rz8amarqegxpuyl0oi25hwj3w.png)
we know that the volume of a sphere is given by
![v= (4)/(3) \pi r^(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/2q4n2e3z8mcctxyt9mma58j7l30i6lzqgw.png)
substituting into the formula we have
![v= (4)/(3) \ *3.142*2^(3) \\v=\frac{4*3.142*8}3} \\v= (100.54)/(3) \\v= 33.52in^(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/sv8zz2q0la4lesluc77ezt9sevfuubx2u5.png)