Question

Which equation describes this line?

A. y-2 = 3(x - 4)
B. y- 1 = 3(x - 13)
C. y - 4 = 3 (x - 2)
D. y - 4 = 3(x + 2)
pleaseeeeee:'(​

Answer 1

D

Explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Calculate m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (- 2, 4) and (x₂, y₂ ) = (1, 13) ← 2 points on the line

m =
`(13-4)/(1+2)` =
`(9)/(3)` = 3

Use either of the 2 points for (a, b)

Using (a, b) = (- 2, 4), then

y - 4 = 3(x - (- 2)), that is

y - 4 = 3(x + 2) → D

Answer 2

D. y - 4 = 3(x + 2)

Explanation:

hello :

1) this line passes trough (-2,4) because : 4-4 =3(-2+2) means : 0=0 (true)

2) this line passes trough (1,13) because : 13-4 =3(1+2) means : 9=9

(true)