Answer:
B
Explanation:
Given the 2 equations
- 2x = 4y + 6 → (1)
2(2y + 3) = 3x - 5 → (2)
Distribute left side of (2)
4y + 6 = 3x - 5 → (2)
Substitute 4y + 6 = - 2x into (2)
- 2x = 3x - 5 ( subtract 3x from both sides )
- 5x = - 5 ( divide both sides by - 5 )
x = 1
Substitute x = 1 into either of the 2 equations and solve for y
Substituting into (1)
- 2(1) = 4y + 6
- 2 = 4y + 6 ( subtract 6 from both sides )
- 8 = 4y ( divide both sides by 4 )
y = - 2
Solution is (1, - 2 ) → B