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Write an equation in point-slope form of the line that passes through (3, -8) and (7,-2).

User Stefanosn
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2 Answers

5 votes

Answer:

A line that passes through (3, -8) and (7,-2).

Denote equation of that line: y = ax + b

=> Slope a can be directly determined by:

a = (7 - 3)/(-2 - -8) = 4/6 = 2/3

=> y = (2/3)x + b

This line passes (3, -8), then: -8 = (2/3)*3 + b => -8 = 2 + b => b = -10

=> y =(2/3)x - 10

There are other ways to find equation of line.

Hope this helps!

:)

User KenHBS
by
3.6k points
6 votes

Answer:


(3)/(2) x+10

Explanation:


(y1 - y2)/(x1 - x2) \\ ( - 8 - ( - 2))/(3 - 7) \\ ( - 8 + 2)/( - 4) \\ ( - 6)/( - 4) \\ = (3)/(2)

y=3/2x+c

-8-3/2=c

c=10

User Sajida
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3.4k points