Question

Which is the equation of a line that has a slope of -2/3 and passes through point (-3, -1)? y=-2/3x+1.

y=-2/3x+3.
y=-2/3x-1.
y=-2/3x-3

Answer 1

y = -2/3x - 3

Explanation:

First, write the equation using the slope. It should look like this: y = -2/3x + b. Next, find the y intercept by plugging in the point. This is what it looks like: -1 = -2/3(-3) + b. Multiply -2/3 by -3 to get 2. This is what it should look like now: -1 = 2 + b. Subtract 3 from both sides to get -3 = b. Go back to your original equation and plug in -3 for b. This is your final equation:

y = -2/3x - 3

Hope this helped! :)