Question

SOMEONE help! due today
25 POINTS
SEE ATTACHED.

Answer 1

Q4. 2H₂ + O₂ ⟶ 2H₂O; 5; 2

Q5. 24; 30; H₂; 0; 5

Step-by-step explanation:

Q4.

The equation for the reaction is

2H₂ + O₂ ⟶ 2H₂O

One O₂ molecule reacts with 2H₂ molecules.

`\text{No. of O$_(2)$ molecules} = \text{10 H$_(2)$ molecules } * \frac{\text{1 O$_(2)$ molecule }}{\text{2 H$_(2)$ molecules}} = \textbf{5 O$_{\textbf{2}}$ molecules}\\\\\text{Ten hydrogen molecules react with $\textbf{five}$ oxygen molecules.}`

We started with seven oxygen molecules. Five of them reacted, so

Two O₂ molecules did not react.

Q5.

Two water molecules form from two hydrogen molecules.

`\text{No. of H$_(2)$O molecules} = \text{24 H$_(2)$ molecules } * \frac{\text{2 H$_(2)$O molecules}}{\text{2 H$_(2)$ molecules}} = \textbf{24 H$_{\textbf{2}}$O molecules}`Two water molecules form from one oxygen molecule

`\text{No. of H$_(2)$O molecules} = \text{15 O$_(2)$ molecules } * \frac{\text{2 H$_(2)$O molecules}}{\text{1 O$_(2)$ molecules}} = \textbf{30 H$_{\textbf{2}}$O molecules}`Hydrogen forms fewer water molecules of water, so

Hydrogen is the limiting reactant.

The 24 hydrogen molecules will be completely used up.

The number of hydrogen molecules remaining at the end of the reaction is zero.

They have reacted with 12 O₂ molecules.

The number of O₂ molecules remaining is 17 - 12 = 5