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9 votes
Please help pls pls help pls belp

Please help pls pls help pls belp-example-1
User Cyril Mestrom
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1 Answer

12 votes
12 votes

Answer:

After 1 second, the ball will reach a maximum height of 16 feet

Explanation:

The height of the ball after t seconds: h(t) = -16t^2 + 32t

The graph of this quadratic function is parabola which opens downwards. The vertex of a quadratic equation is the maximum or minimum point on the equation's parabola

t = -b/2a = -(32)/2(-16) = -32/-32 = 1 second

then

h(t) = -16(1)^2 + 32(1) = -16 + 32 = 16

After 1 second, the ball will reach a maximum height of 16 feet

User Ezzored
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