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3 votes
20≥8+4.99x please I could get an F.

User Amos
by
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1 Answer

5 votes

Answer:


\begin{bmatrix}\mathrm{Solution:}\:&\:x\le (1200)/(499)\:\\ \:\mathrm{Decimal:}&\:x\le \:2.40480\dots \\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:(1200)/(499)]\end{bmatrix}

Explanation:


20\ge \:8+4.99x\\Switch\:sides\\8+4.99x\le \:20\\\mathrm{Multiply\:both\:sides\:by\:}100\\8\cdot \:100+4.99x\cdot \:100\le \:20\cdot \:100\\Refine\\800+499x\le \:2000\\\mathrm{Subtract\:}800\mathrm{\:from\:both\:sides}\\800+499x-800\le \:2000-800\\Simplify\\499x\le \:1200\\\mathrm{Divide\:both\:sides\:by\:}499\\(499x)/(499)\le (1200)/(499)\\Simplify\geq \\x\le (1200)/(499)

User FeuGene
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5.5k points