Question

Given the quadrant of q in standard position and a trigonometric function value of q , find the exact value for the indicated function. II, sin q = 0.4; sec q

Answer 1

9514 1404 393

Answer:

-(5/21)√21

Explanation:

In the second quadrant, the cosine and secant are negative, so the value of interest is ...

sec(q) = -1/√(1 -0.4²) = -1/√0.84 = -√(25/21)

sec(q) = (-5√21)/21