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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second.


y=-16x^(2) +188x+103

User Djv
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1 Answer

3 votes

Answer:(47/8, 2621/4)

Explanation:

Use the formula x= -b/2a to find the maximum and minimum

User Anakhand
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